This is a step-by-step guide to create a "contract-first" web service with Apache CXF. It's a lot easier than doing the same thing with Spring-WS. The project uses standard Maven directory layout. Define the data types ( src/main/resources/hello.xsd ): <xs:schema xmlns:xs="http://www.w3.org/200... Define the service ( src/main/resources/hello.wsdl ): <?xml version='1.1' encoding='UTF-8'?> <wsdl:de... Create pom.xml : <project xmlns="http://maven.apache.org/POM/4.... Generate jaxb bindings: $ mvn generate-sources Code the web service ( src/main/java/com/example/cxfdemo/HelloPortImpl.java ): package com.example.cxfdemo; import javax.j... Declare the CXF servlet in web.xml ( src/main/webapp/WEB-INF/web.xml ): <?xml version="1.0" encoding="UTF-8"?> <web-app... Wire up the web service implementation ( src/main/webapp/WEB-INF/cxf-servlet.xml ): <?xml version="1.0" encoding="UTF-8"?> <beans x... Build the WAR: $ mvn clean package After the webapp is deployed (Tomcat running on port 8080), the web service (WSDL) is available via...

After a user resets a password, I want to force the user to change the password before she gets access to secured content. This is usually done with a servlet filter. But with Spring MVC, you can also use a HandlerInterceptor . According to Spring JavaDoc: HandlerInterceptor is basically similar to a Servlet 2.3 Filter, but in contrast to the latter it just allows custom pre-processing with the option of prohibiting the execution of the handler itself, and custom post-processing. Filters are more powerful, for example they allow for exchanging the request and response objects that are handed down the chain. Note that a filter gets configured in web.xml, a HandlerInterceptor in the application context. As a basic guideline, fine-grained handler-related preprocessing tasks are candidates...

This is probably the easiest way to create a web service in JAX-WS. There are no external dependencies other than Java EE. Assuming that you build the web service as a webapp (say jaxws-example.war), the pom.xml can be as simple as: <project xmlns="http://maven.apache.org/POM/4.0.0"... You can implement and deploy the web service in 3 easy steps: Code the service as a POJO (annotate class to expose it as a web service) package jaxws; import javax.jws.WebMethod; ... Declare the POJO as a servlet in WEB-INF/web.xml : <?xml version="1.0" encoding="UTF-8"?> <web-app... Build the webapp, and deploy the resulting war: mvn package The only catch is, this only works for a Java EE 5+ compliant container such as WebLogic or JBoss. It does not work for a simple servlet...

I have an old Samung phone to be used as a toy. After restoring back to factory image and power on, I was stuck at the activate service screen. Unfortunately, the four corner magic touch did not work. So I did quite a bit of digging and this is what worked on my Samsung Continuum: Press emergency call button, then at the dialer, press * # 8 3 7 8 6 6 3 3 , press the Home key From the home screen, tap phone icon, Dial * # 2 2 7 4 5 9 2 7 Enter SPC code: ______ displays tap in white box to show virtual keyboard, enter 6 digit code (default: 000000), tap OK Select “Hidden menu Enable”, tap OK From...

Junit does not support specifying execution order of tests until 4.11. The methods were simply invoked in the order returned by the reflection API. So, the tests are executed in a unspecified but deterministic order, i.e., you have no control over the order of execution, but if you repeat the tests, they are run in the same sequence each time. For version 4.11, you can specify the order with the FixMethodOrder annotation: import org.junit.runners.MethodSorters; imp... From the release notes : Test execution order By design, JUnit does not specify the execution order of test method invocations. Until now, the methods were simply invoked in the order returned by the reflection API. However, using the JVM order is unwise since the Java platform does not specify...

Use OpenSSL's s_client command to fetch a page manually: $ openssl s_client -connect localhost:443 -state -... Sample session for Google: $ openssl s_client -connect www.google.com:443 -st... Resource: SSL/TLS Strong Encryption: FAQ

Spring MVC 3.1 can send either JSON or HTML response on the same URL, depending on the type of response requested. With this mechanism, a page can be sent when directly requested from a link, but a JSON response can be sent in response to an AJAX request. This is the controller code: package com.example; import java.util.Map; ... In the above example, JSON response will be sent when the HTTP request contains header "Accept: application/json". HTML response will be sent then the header is "Accept: */*", or "Accept: text/html", or anything else. You can add a limitation that the HTML response does not produce "application/json". But then the question is which response will be sent when the HTTP header is "Accept: */*"? Both methods will...

This may or may not be useful, but I did the research so here's the code. import org.springframework.beans.factory.annotatio...

Mapping Java objects to Jackson JSON is pretty simple. But if you name a JSON field wrong, you'll get the "Unrecognized field ... (Class ...), not marked as ignorable" error. The rule for mapping a Java bean attribute name to a JSON field name is: lower all leading capital letters until the first lower case letter . For example, this Java class: package com.example; public class Person { ... maps to this JSON string: { "firstName": "Jane", "lastName": "... Test code: package com.example; import java.net.URL; ...

This code snippet gets the default keystore used by the Java keytool and displays the list of aliases along with the key type (certificate or private key). import java.io.File; import java.io.FileInputSt... The default keystore used by the above code is: $HOME/.keystore .