This is a utility to convert a byte array to hex string, and to convert a hex string back to the original. To convert a String to hex, you must call String.getBytes() first. The utility does not pretend to know your string encoding. public class StringHexUtil { public static ... This also works: String binaryToHex(byte[] data) { StringBui...

Syntax highlighted XML schema for JSF 2.0 Application Configuration Resource File ( faces-config.xml ). Almost 3000 lines! <?xml version="1.0" encoding="UTF-8"?> <xsd:sch...

Maven repositories are a central part of the Maven build system. Maven resolves dependencies through repositories. There are two types of repositories: local and remote . The local repository stores local build artifacts (when you do mvn install ) and caches artifacts from remote repositories. It is usually located on the local file system at $USER_HOME/.m2/repository . Remote repositories are located on the network and accessed by URLs ( http:// or file:// etc). The central Maven repository is: repo1.maven.org . The Java EE repositories are located at: http://download.java.net/maven/2/ and http://download.java.net/maven/1/ . Remote repositories can also be set up on the company intranet within a company's firewall. The central repository is automatically configured after installation. You can add additional repositories in settings.xml , for example: <?xml version="1.0" encoding="UTF-8"?> <setting......

Read the whole contents of a file into a String. It's better to read the whole file as bytes and convert to String than to read the file line by line and concatenate the lines. String getFileContents(String fileName) throws... Using java.nio : import java.io.FileInputStream; import java...

For Java arrays, the class name is [ followed by an encoded name of the element class. The number of [ characters represents the number of dimensions of the array. The class name encoding is following: Element Type Encoding boolean Z byte B char C class or interface L classname; double D float F int I long J short S Example: public class ClassNameEncoding { public sta...

There are two distinct ways to process XPath: with namespace and without namespace. The code is different depending on whether the parser is namespace aware. Code without namespace: import java.io.*; import javax.xml.parsers.*; ... code with namespace: import java.io.*; import java.util.Iterator; ... XML without namespace: <?xml version="1.0" encoding="UTF-8" standalone="n... XML with namespace: <?xml version="1.0" encoding="UTF-8" standalone="n... The same XPath expression works for both XML files when the parser is not namespace aware. When the parser is namespace aware, you have to adjust the XPath accordingly depending on whether the XML has namespace declarations: " /test-license/licensee/name/text() " works for the XML file without namespace, while " /p:test-license/p:licensee/p:name/text() " works for the XML file with namespace.

For XML resources, Android returns an XmlPullParser reference. I tried the RSSReader example from xmlpull.org , it failed both on the Android emulator and with xpp3-1.1.4c . This is an example for XmlPullParser usage. Since the XmlPullParser is event based, a callback mechanism works better. Java code: import java.io.*; import java.net.*; import ... The XML file used: <?xml version="1.0" encoding="UTF-8"?> <catalog...

This is the opposite of parsing. You can use javax.xml.transform.Transformer to output a DOM tree to a file. import java.io.*; import javax.xml.parsers.Docu...

You can use the javax.xml.transform.Transformer class to "transform" an XML stream (string in this case) to a DOM tree - effectively parsing the XML string. import java.io.*; import javax.xml.transform.Tr...

Use javax.xml.parsers.DocumentBuilder to parse xml. DocumentBuilder.parse() takes: java.io.File org.xml.sax.InputSource java.io.InputStream java.lang.String as a URI to an XML document Example code: import java.io.*; import javax.xml.parsers.Docu...